X^2-5y=27

Solution for X^2-5y=27 equation:

X^2-5X=27

We move all terms to the left:

X^2-5X-(27)=0

a = 1; b = -5; c = -27;
Δ = b2-4ac
Δ = -52-4·1·(-27)
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{133}}{2*1}=\frac{5-\sqrt{133}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{133}}{2*1}=\frac{5+\sqrt{133}}{2}
$